Activity: Analyzing the Magnitude and Direction of Magnetic Force Solution

Computed Magnetic Force Values

Case	Force (N)	Charge (C)	Velocity (m/s)	Magnetic Field Strength (T)
A	0.12 N	2.0 × 10⁻⁶ C	3.0 m/s, East	20 T
B	2.0 × 10⁻¹³ N	-1.6 × 10⁻¹⁹ C	2.5 × 10⁶ m/s, North	0.5 T, Upward
C	0.08 N	2.0 × 10⁻⁶ C	4.0 m/s, South	0.1 T, West
D	0.20 N	1.0 × 10⁻⁶ C	0.5 m/s	0.4 T, Downward
E	3.2 × 10⁻⁷ N	3.2 × 10⁻⁶ C	2.0 m/s, West	0.05 T, North
F	0.15 N	5.0 × 10⁻⁶ C	1.5 m/s, North	20 T
G	9.6 × 10⁻¹³ N	1.6 × 10⁻¹⁹ C	3.0 × 10⁶ m/s, East	0.2 T, Downward
H	0.25 N	5.0 × 10⁻⁶ C	5.0 m/s, West	0.1 T, South
I	0.10 N	2.5 × 10⁻⁶ C	2.0 m/s	0.2 T, East
J	9.0 × 10⁻⁷ N	-3.0 × 10⁻⁶ C	1.0 m/s, South	0.3 T, Upward

Solutions Per Letter

A: Find \( B \)

\( B = \frac{0.12 \text{ N}}{(2.0 × 10^{-6} \text{ C})(3.0 \text{ m/s})} = 20 \text{ T} \)

B: Find \( F \)

\( F = (-1.6 × 10^{-19} \text{ C})(2.5 × 10^{6} \text{ m/s})(0.5 \text{ T}) = -2.0 × 10^{-13} \text{ N} \)

C: Find \( q \)

\( q = \frac{0.08 \text{ N}}{(4.0 \text{ m/s})(0.1 \text{ T})} = 2.0 × 10^{-6} \text{ C} \)

D: Find \( v \)

\( v = \frac{0.20 \text{ N}}{(1.0 × 10^{-6} \text{ C})(0.4 \text{ T})} = 0.5 \text{ m/s} \)

E: Find \( F \)

\( F = (3.2 × 10^{-6} \text{ C})(2.0 \text{ m/s})(0.05 \text{ T}) = 3.2 × 10^{-7} \text{ N} \)

J: Find \( F \)

\( F = (-3.0 × 10^{-6} \text{ C})(1.0 \text{ m/s})(0.3 \text{ T}) = -9.0 × 10^{-7} \text{ N} \)